1、题目描述
题意:找出数组中总和≥target的长度最小的连续子数组的长度。
2、分析
3、实现代码
#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <queue>
#include <stack>
#include <map>
#include <math.h>
#include <unordered_map>
using namespace std;
class Solution {
public:
int minSubArrayLen(int target, vector<int>& nums) {
int min_len = INT32_MAX;
int beg = 0;//滑动窗口左边界
int sum = 0;
for(int i = 0; i < nums.size(); i++){
sum += nums[i];
//①累计和sum<target就不断拓宽右边界i
if(sum < target){
continue;
//②一旦累计和sum≥target,就要收缩左边界
}else{
//一直收缩到sum不在≥target
while(beg <= i && sum >= target){
min_len = min(min_len, i - beg + 1);
sum = sum - nums[beg];
beg++;
}
}
}
//返回最终的结果
return min_len == INT32_MAX ? 0 : min_len;
}
};
int main()
{
Solution s1;
//int target = 7;
//vector<int> nums{2,3,1,2,4,3};
//int target = 4;
//vector<int> nums{1,4,4};
int target = 11;
vector<int> nums{1,1,1,1,1,1,1,1};
cout << s1.minSubArrayLen(target, nums) << endl;
}