1/1
1.2m
2.6m0.35mF = 290kN/mM = 10.4
kN/m
C20
HPB235
1
e = M / F = 10.4 / 290 = 0.036 m
pmax = F/b(1 + 6e/b) = 290 / 2.6 (1 + 6 0.036 / 2.6) = 120.8kN/m2pmin = F/b(1 -6e/b) = 290 / 2.6 (1 -6 0.036 / 2.6) = 120.8kN/m22
h = 350mm
100mmh0 = 350 -50 =300mmC20f = 1.10kN/mm2
HPB235
fy = 210N/mm2
b1 = b/2 –b0/2 = 2600/2 –(1055 + 60)/2 = 1055mmI-IpnI = 102.3 +2600-1055 + 60
/2600
120.8 –102.3=112.9kN/m2
pn = 1/2pnmax + pnmin=1/2120.8 + 112.9= 116.9kN/m2V = pnlb1 + 0.06= 116.911.055 + 0.06= 130.3kN
7.5.3-1
βh = 1.0
0.7βhftbh0 = 0.71.01.11000300 = 231kN > 130.3kN3
M = 1/2 pnlbl+0.062 = 1/2116.911.055 + 0.06
2 = 72.67 kN.m
As = M / (0.9fyH0) = 72.67 106 / (0.9210300 ) = 1282mm2
φ14@110As = 1399mm24
pnmax120.8120.8pnmin102.3102.3V130.3127.4Mmk:@MSITStore:C:\\Program%20Files%20(x86)\\LiZheng\\JieGou21\\TBexam\\cy\\Tbc...2013-12-01
